1880 United States presidential election in Nebraska

1880 United States presidential election in Nebraska

← 1876 November 2, 1880 1884 →
 
Nominee James A. Garfield Winfield S. Hancock
Party Republican Democratic
Home state Ohio Pennsylvania
Running mate Chester A. Arthur William H. English
Electoral vote 3 0
Popular vote 54,979 28,523
Percentage 62.87% 32.62%

County Results

President before election

Rutherford B. Hayes
Republican

Elected President

James A. Garfield
Republican

The 1880 United States presidential election in Nebraska took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Nebraska voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 30.25%.

With 62.87% of the popular vote, Nebraska would be Garfield's second strongest victory in terms of percentage in the popular vote after Vermont.[1]

  1. ^ "1880 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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